Hoa huu co_chuong 17

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Chia sẻ tài liệu: hoa huu co_chuong 17 thuộc Bài giảng khác

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Philip Dutton
University of Windsor, Canada
N9B 3P4

Prentice-Hall © 2002

General Chemistry
Principles and Modern Applications
Petrucci • Harwood • Herring
8th Edition
Chapter 17: Acids and Bases
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 2 of 47
Contents
17-1 The Arrhenius Theory: A Brief Review
17-2 Brønsted-Lowry Theory of Acids and Bases
17-3 The Self-Ionization of Water and the pH Scale
17-4 Strong Acids and Strong Bases
17-5 Weak Acids and Weak Bases
17-6 Polyprotic Acids
17-7 Ions as Acids and Bases
17-8 Molecular Structure and Acid-Base Behavior
17-8 Lewis Acids and Bases
Focus On Acid Rain.


Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 3 of 47
17-1 The Arrhenius Theory:
A Brief Review
HCl(g) → H+(aq) + Cl-(aq)
H2O
Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) → H2O(l) + Na+(aq) + Cl-(aq)
H+(aq) + OH-(aq) → H2O(l)
Arrhenius theory did not handle non OH- bases such as ammonia very well.
Prentice-Hall © 2002
General Chemistry: Chapter 17
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17-2 Brønsted-Lowry Theory of
Acids and Bases
An acid is a proton donor.
A base is a proton acceptor.
NH3 + H2O  NH4+ + OH-
NH4+ + OH-  NH3 + H2O
base
acid
base
acid
conjugate acid
conjugate base
Prentice-Hall © 2002
General Chemistry: Chapter 17
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Base Ionization Constant
NH3 + H2O  NH4+ + OH-
base
acid
conjugate
acid
conjugate
base
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General Chemistry: Chapter 17
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Acid Ionization Constant
CH3CO2H + H2O  CH3CO2- + H3O+
base
acid
conjugate
acid
conjugate
base
Prentice-Hall © 2002
General Chemistry: Chapter 17
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Table 17.1 Relative Strengths of Some Brønsted-Lowry Acids and Bases
HClO4 + H2O  ClO4- + H3O+
NH4+ + CO32-  NH3 + HCO3-
HCl + OH-  Cl- + H2O
H2O + I-  OH- + HI
H2O + I-  OH- + HI
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General Chemistry: Chapter 17
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17-3 The Self-Ionization of Water and
the pH Scale
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General Chemistry: Chapter 17
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Ion Product of Water
H2O + H2O  H3O+ + OH-
base
acid
conjugate
acid
conjugate
base
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 10 of 47
pH and pOH
The potential of the hydrogen ion was defined in 1909 as the negative of the logarithm of [H+].
pH = -log[H3O+]
pOH = -log[OH-]
-logKW = -log[H3O+]-log[OH-]= -log(1.010-14)
KW = [H3O+][OH-]= 1.010-14
pKW = pH + pOH= -(-14)
pKW = pH + pOH = 14
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General Chemistry: Chapter 17
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pH and pOH Scales
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General Chemistry: Chapter 17
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17-4 Strong Acids and Bases
HCl CH3CO2H
Thymol Blue Indicator
pH < 1.2 < pH < 2.8 < pH
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General Chemistry: Chapter 17
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17-5 Weak Acids and Bases
Acetic Acid
HC2H3O2 or CH3CO2H
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General Chemistry: Chapter 17
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Weak Acids
Ka=
= 1.810-5
[CH3CO2H]
[CH3CO2-][H3O+]
pKa= -log(1.810-5) = 4.74
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General Chemistry: Chapter 17
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Table 17.3 Ionization Constants of Weak Acids and Bases
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General Chemistry: Chapter 17
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Example 17-5
Determining a Value of KA from the pH of a Solution of a Weak Acid.
Butyric acid, HC4H7O2 (or CH3CH2CH2CO2H) is used to make compounds employed in artificial flavorings and syrups. A 0.250 M aqueous solution of HC4H7O2 is found to have a pH of 2.72. Determine KA for butyric acid.
HC4H7O2 + H2O  C4H77O2 + H3O+ Ka = ?
Solution:
For HC4H7O2 KA is likely to be much larger than KW. Therefore assume self-ionization of water is unimportant.
Prentice-Hall © 2002
General Chemistry: Chapter 17
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Example 17-5
HC4H7O2 + H2O  C4H7O2 + H3O+
Initial conc. 0.250 M 0 0
Changes -x M +x M +x M
Eqlbrm conc. (0.250-x) M x M x M
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 18 of 47
Example 17-5
Log[H3O+] = -pH = -2.72
HC4H7O2 + H2O  C4H77O2 + H3O+
[H3O+] = 10-2.72 = 1.910-3 = x
Ka= 1.510-5
Check assumption: Ka >> KW.
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General Chemistry: Chapter 17
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Percent Ionization
HA + H2O  H3O+ + A-
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General Chemistry: Chapter 17
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Percent Ionization
Ka =
[H3O+][A-]
[HA]
Ka =
n
H3O+
A-
n
HA
n
1
V
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 21 of 47
17-6 Polyprotic Acids
H3PO4 + H2O  H3O+ + H2PO4-
H2PO4- + H2O  H3O+ + HPO42-
HPO42- + H2O  H3O+ + PO43-
Phosphoric acid:
A triprotic acid.
Ka = 7.110-3
Ka = 6.310-8
Ka = 4.210-13
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 22 of 47
Phosphoric Acid
Ka1 >> Ka2
All H3O+ is formed in the first ionization step.
H2PO4- essentially does not ionize further.
Assume [H2PO4-] = [H3O+].
[HPO42-] Ka2 regardless of solution molarity.
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General Chemistry: Chapter 17
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Table 17.4 Ionization Constants of Some Polyprotic Acids
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General Chemistry: Chapter 17
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Example 17-9
Calculating Ion Concentrations in a Polyprotic Acid Solution.
For a 3.0 M H3PO4 solution, calculate:
(a) [H3O+]; (b) [H2PO4-]; (c) [HPO42-] (d) [PO43-]
H3PO4 + H2O  H2PO4- + H3O+
Initial conc. 3.0 M 0 0
Changes -x M +x M +x M
Eqlbrm conc. (3.0-x) M x M x M
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 25 of 47
Example 17-9
H3PO4 + H2O  H2PO4- + H3O+
[H3O+] [H2PO4-]
[H3PO4]
Ka=
x · x
(3.0 – x)
=
Assume that x << 3.0
= 7.110-3
x2 = (3.0)(7.110-3) x = 0.14 M
[H2PO4-] = [H3O+] = 0.14 M
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 26 of 47
Example 17-9
H2PO4- + H2O  HPO42- + H3O+
Initial conc. 0.14 M 0 0.14 M
Changes -y M +y M +y M
Eqlbrm conc. (0.14 - y) M y M (0.14 +y) M
y << 0.14 M y = [HPO42-] = 6.310-8
Prentice-Hall © 2002
General Chemistry: Chapter 17
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Example 17-9
HPO4- + H2O  PO43- + H3O+
[H3O+] [HPO42-]
[H2PO4-]
Ka=
(0.14)[PO43-]
6.310-8
=
= 4.210-13 M
[PO43-] = 1.910-19 M
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 28 of 47
Sulfuric Acid
Sulfuric acid:
A diprotic acid.
H2SO4 + H2O  H3O+ + HSO4-
HSO4- + H2O  H3O+ + SO42-
Ka = very large
Ka = 1.96
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 29 of 47
General Approach to Solution Equilibrium Calculations
Identify species present in any significant amounts in solution (excluding H2O).
Write equations that include these species.
Number of equations = number of unknowns.
Equilibrium constant expressions.
Material balance equations.
Electroneutrality condition.
Solve the system of equations for the unknowns.
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 30 of 47
17-7 Ions as Acids and Bases
NH4+ + H2O  NH3 + H3O+
base
acid
CH3CO2- + H2O  CH3CO2H + OH-
base
acid
Ka Kb = Kw
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 31 of 47
Hydrolysis
Water (hydro) causing cleavage (lysis) of a bond.
Na+ + H2O → Na+ + H2O
NH4+ + H2O → NH3 + H3O+
Cl- + H2O → Cl- + H2O
No reaction
No reaction
Hydrolysis
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General Chemistry: Chapter 17
Slide 32 of 47
17-8 Molecular Structure and
Acid-Base Behavior
Why is HCl a strong acid, but HF is a weak one?
Why is CH3CO2H a stronger acid than CH3CH2OH?

There is a relationship between molecular structure and acid strength.
Bond dissociation energies are measured in the gas phase and not in solution.
Prentice-Hall © 2002
General Chemistry: Chapter 17
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Strengths of Binary Acids
HI HBr HCl HF
160.9 > 141.4 > 127.4 > 91.7 pm
297 < 368 < 431 < 569 kJ/mol
Bond length
Bond energy
109 > 108 > 1.3106 >> 6.610-4
Acid strength
HF + H2O → [F-·····H3O+]  F- + H3O+
ion pair
H-bonding
free ions
Prentice-Hall © 2002
General Chemistry: Chapter 17
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Strengths of Oxoacids
Factors promoting electron withdrawal from the OH bond to the oxygen atom:
High electronegativity (EN) of the central atom.
A large number of terminal O atoms in the molecule.
H-O-Cl H-O-Br
ENCl = 3.0 ENBr= 2.8
Ka = 2.910-8 Ka = 2.110-9
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General Chemistry: Chapter 17
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Ka 103 Ka =1.310-2
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General Chemistry: Chapter 17
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Strengths of Organic Acids
C
O
C
O
H
H
··
··
H
H
O
C
H
H
··
··
H
H
C
H
H
Ka = 1.810-5 Ka =1.310-16
acetic acid ethanol
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General Chemistry: Chapter 17
Slide 37 of 47
Focus on the Anions Formed
O
C
H
··
··
H
H
C
H
H
··
-
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General Chemistry: Chapter 17
Slide 38 of 47
Structural Effects
C
O
C
O
H
-
··
H
H
C
H
H
H
Ka = 1.810-5

Ka = 1.310-5
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 39 of 47
Structural Effects
C
O
C
O
H
-
··
H
H
Ka = 1.810-5

Ka = 1.410-3
C
O
C
O
H
-
··
H
Cl
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General Chemistry: Chapter 17
Slide 40 of 47
Strengths of Amines as Bases
N
H
H
H
··
N
Br
H
H
··
pKb = 4.74 pKa = 7.61
ammonia bromamine
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General Chemistry: Chapter 17
Slide 41 of 47
Strengths of Amines as Bases
C
H
H
H
C
H
H
C
H
H
H
C
H
H
C
H
H
H
C
H
H
pKb = 4.74 pKa = 3.38 pKb = 3.37
methylamine ethylamine propylamine
NH2
NH2
NH2
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General Chemistry: Chapter 17
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Resonance Effects
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General Chemistry: Chapter 17
Slide 43 of 47
Inductive Effects
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General Chemistry: Chapter 17
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17-9 Lewis Acids and Bases
Lewis Acid
A species (atom, ion or molecule) that is an electron pair acceptor.
Lewis Base
A species that is an electron pair donor.
base
acid
adduct
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General Chemistry: Chapter 17
Slide 45 of 47
Showing Electron Movement
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General Chemistry: Chapter 17
Slide 46 of 47
CO2 + H2O  H2CO3
H2CO3 + H2O  HCO3- + H3O+
3 NO2 + H2O  2 HNO3 + NO
Prentice-Hall © 2002
General Chemistry: Chapter 17
Slide 47 of 47
Chapter 17 Questions

Develop problem solving skills and base your strategy not on solutions to specific problems but on understanding.

Choose a variety of problems from the text as examples.

Practice good techniques and get coaching from people who have been here before.
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