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Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 1 of 29
Philip Dutton
University of Windsor, Canada
Prentice-Hall © 2002
Chapter 4: Chemical Reactions
General Chemistry
Principles and Modern Applications
Petrucci • Harwood • Herring
8th Edition
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 2 of 29
Contents
4-1 Chemical Reactions and Chemical Equations
4-2 Chemical Equations and Stoichiometry
4-3 Chemical Reactions in Solution
4-4 Determining the Limiting reagent
4-5 Other Practical Matters in Reaction Stoichiometry
Focus on Industrial Chemistry
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 3 of 29
4-1 Chemical Reactions and
Chemical Equations
As reactants are converted to products we observe:
Color change
Precipitate formation
Gas evolution
Heat absorption or evolution
Chemical evidence may be necessary.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 4 of 29
Chemical Reaction
Nitrogen monoxide + oxygen → nitrogen dioxide
Step 1: Write the reaction using chemical symbols.
NO + O2 → NO2
Step 2: Balance the chemical equation.
2
1
2
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 5 of 29
Molecular Representation
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 6 of 29
Balancing Equations
Never introduce extraneous atoms to balance.
NO + O2 → NO2 + O
Never change a formula for the purpose of balancing an equation.
NO + O2 → NO3
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 7 of 29
Balancing Equation Strategy
Balance elements that occur in only one compound on each side first.
Balance free elements last.
Balance unchanged polyatomics as groups.
Fractional coefficients are acceptable and can be cleared at the end by multiplication.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 8 of 29
Example 4-2
Writing and Balancing an Equation: The Combustion of a Carbon-Hydrogen-Oxygen Compound.
Liquid triethylene glycol, C6H14O4, is used a a solvent and plasticizer for vinyl and polyurethane plastics. Write a balanced chemical equation for its complete combustion.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 9 of 29
C6H14O4 + O2 → CO2 + H2O
6
2. Balance H.
2 C6H14O4 + 15 O2 → 12 CO2 + 14 H2O
4. Multiply by two
Example 4-2
3. Balance O.
and check all elements.
Chemical Equation:
1. Balance C.
6 7
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 10 of 29
4-2 Chemical Equations and Stoichiometry
Stoichiometry includes all the quantitative relationships involving:
atomic and formula masses
chemical formulas.
Mole ratio is a central conversion factor.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 11 of 29
Example 4-3
Relating the Numbers of Moles of Reactant and Product.
How many moles of H2O are produced by burning 2.72 mol H2 in an excess of O2?
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 12 of 29
Example 4-6
Additional Conversion Factors ina Stoichiometric Calculation: Volume, Density, and Percent Composition.
An alloy used in aircraft structures consists of 93.7% Al and 6.3% Cu by mass. The alloy has a density of 2.85 g/cm3. A 0.691 cm3 piece of the alloy reacts with an excess of HCl(aq). If we assume that all the Al but none of the Cu reacts with HCl(aq), what is the mass of H2 obtained?
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 13 of 29
Example 4-6
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 14 of 29
2 Al + 6 HCl → 2 AlCl3 + 3 H2
Example 4-6
We need 5 conversion factors!
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 15 of 29
4-3 Chemical Reactions in Solution
Close contact between atoms, ions and molecules necessary for a reaction to occur.
Solvent
We will usually use aqueous (aq) solution.
Solute
A material dissolved by the solvent.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 16 of 29
Molarity
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 17 of 29
Preparation of a Solution
Weigh the solid sample.
Dissolve it in a volumetric flask partially filled with solvent.
Carefully fill to the mark.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 18 of 29
Calculating the mass of Solute in a solution of Known Molarity.
We want to prepare exactly 0.2500 L (250 mL) of an 0.250 M K2CrO4 solution in water. What mass of K2CrO4 should we use?
Plan strategy:
Example 4-6
Volume → moles → mass
We need 2 conversion factors!
Write equation and calculate:
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 19 of 29
Solution Dilution
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 20 of 29
Preparing a solution by dilution.
A particular analytical chemistry procedure requires 0.0100 M K2CrO4. What volume of 0.250 M K2CrO4 should we use to prepare 0.250 L of 0.0100 M K2CrO4?
Example 4-10
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 21 of 29
4-4 Determining Limiting Reagent
The reactant that is completely consumed determines the quantities of the products formed.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 22 of 29
Determining the Limiting Reactant in a Reaction.
Phosphorus trichloride , PCl3, is a commercially important compound used in the manufacture of pesticides, gasoline additives, and a number of other products. It is made by the direct combination of phosphorus and chlorine
P4 (s) + 6 Cl2 (g) → 4 PCl3 (l)
What mass of PCl3 forms in the reaction of 125 g P4 with 323 g Cl2?
Example 4-12
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 23 of 29
Example 4-12
nCl2 = 323 g Cl2 × = 4.56 mol Cl2
1 mol Cl2
70.91 g Cl2
actual = 4.55 mol Cl2/mol P4
theoretical = 6.00 mol Cl2/mol P4
Chlorine gas is the limiting reagent.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 24 of 29
4-5 Other Practical Matters in
Reaction Stoichiometry
Theoretical yield is the expected yield from a reactant.
Actual yield is the amount of product actually produced.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 25 of 29
Theoretical, Actual and Percent Yield
When actual yield = % yield the reaction is said to be quantitative.
Side reactions reduce the percent yield.
By-products are formed by side reactions.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 26 of 29
Consecutive Reactions,
Simultaneous Reactions and
Overall Reactions
Multistep synthesis is often unavoidable.
Reactions carried out in sequence are called consecutive reactions.
When substances react independently and at the same time the reaction is a simultaneous reaction.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 27 of 29
Overall Reactions and Intermediates
The Overall Reaction is a chemical equation that expresses all the reactions occurring in a single overall equation.
An intermediate is a substance produced in one step and consumed in another during a multistep synthesis.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 28 of 29
Focus on Industrial Chemistry
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 29 of 29
Chapter 4 Questions
1, 6, 12, 25, 39, 45, 53, 65, 69, 75, 84, 94, 83, 112
General Chemistry: Chapter 4
Slide 1 of 29
Philip Dutton
University of Windsor, Canada
Prentice-Hall © 2002
Chapter 4: Chemical Reactions
General Chemistry
Principles and Modern Applications
Petrucci • Harwood • Herring
8th Edition
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 2 of 29
Contents
4-1 Chemical Reactions and Chemical Equations
4-2 Chemical Equations and Stoichiometry
4-3 Chemical Reactions in Solution
4-4 Determining the Limiting reagent
4-5 Other Practical Matters in Reaction Stoichiometry
Focus on Industrial Chemistry
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 3 of 29
4-1 Chemical Reactions and
Chemical Equations
As reactants are converted to products we observe:
Color change
Precipitate formation
Gas evolution
Heat absorption or evolution
Chemical evidence may be necessary.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 4 of 29
Chemical Reaction
Nitrogen monoxide + oxygen → nitrogen dioxide
Step 1: Write the reaction using chemical symbols.
NO + O2 → NO2
Step 2: Balance the chemical equation.
2
1
2
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 5 of 29
Molecular Representation
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 6 of 29
Balancing Equations
Never introduce extraneous atoms to balance.
NO + O2 → NO2 + O
Never change a formula for the purpose of balancing an equation.
NO + O2 → NO3
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 7 of 29
Balancing Equation Strategy
Balance elements that occur in only one compound on each side first.
Balance free elements last.
Balance unchanged polyatomics as groups.
Fractional coefficients are acceptable and can be cleared at the end by multiplication.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 8 of 29
Example 4-2
Writing and Balancing an Equation: The Combustion of a Carbon-Hydrogen-Oxygen Compound.
Liquid triethylene glycol, C6H14O4, is used a a solvent and plasticizer for vinyl and polyurethane plastics. Write a balanced chemical equation for its complete combustion.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 9 of 29
C6H14O4 + O2 → CO2 + H2O
6
2. Balance H.
2 C6H14O4 + 15 O2 → 12 CO2 + 14 H2O
4. Multiply by two
Example 4-2
3. Balance O.
and check all elements.
Chemical Equation:
1. Balance C.
6 7
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 10 of 29
4-2 Chemical Equations and Stoichiometry
Stoichiometry includes all the quantitative relationships involving:
atomic and formula masses
chemical formulas.
Mole ratio is a central conversion factor.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 11 of 29
Example 4-3
Relating the Numbers of Moles of Reactant and Product.
How many moles of H2O are produced by burning 2.72 mol H2 in an excess of O2?
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 12 of 29
Example 4-6
Additional Conversion Factors ina Stoichiometric Calculation: Volume, Density, and Percent Composition.
An alloy used in aircraft structures consists of 93.7% Al and 6.3% Cu by mass. The alloy has a density of 2.85 g/cm3. A 0.691 cm3 piece of the alloy reacts with an excess of HCl(aq). If we assume that all the Al but none of the Cu reacts with HCl(aq), what is the mass of H2 obtained?
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 13 of 29
Example 4-6
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 14 of 29
2 Al + 6 HCl → 2 AlCl3 + 3 H2
Example 4-6
We need 5 conversion factors!
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 15 of 29
4-3 Chemical Reactions in Solution
Close contact between atoms, ions and molecules necessary for a reaction to occur.
Solvent
We will usually use aqueous (aq) solution.
Solute
A material dissolved by the solvent.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 16 of 29
Molarity
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 17 of 29
Preparation of a Solution
Weigh the solid sample.
Dissolve it in a volumetric flask partially filled with solvent.
Carefully fill to the mark.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 18 of 29
Calculating the mass of Solute in a solution of Known Molarity.
We want to prepare exactly 0.2500 L (250 mL) of an 0.250 M K2CrO4 solution in water. What mass of K2CrO4 should we use?
Plan strategy:
Example 4-6
Volume → moles → mass
We need 2 conversion factors!
Write equation and calculate:
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 19 of 29
Solution Dilution
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 20 of 29
Preparing a solution by dilution.
A particular analytical chemistry procedure requires 0.0100 M K2CrO4. What volume of 0.250 M K2CrO4 should we use to prepare 0.250 L of 0.0100 M K2CrO4?
Example 4-10
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 21 of 29
4-4 Determining Limiting Reagent
The reactant that is completely consumed determines the quantities of the products formed.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 22 of 29
Determining the Limiting Reactant in a Reaction.
Phosphorus trichloride , PCl3, is a commercially important compound used in the manufacture of pesticides, gasoline additives, and a number of other products. It is made by the direct combination of phosphorus and chlorine
P4 (s) + 6 Cl2 (g) → 4 PCl3 (l)
What mass of PCl3 forms in the reaction of 125 g P4 with 323 g Cl2?
Example 4-12
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 23 of 29
Example 4-12
nCl2 = 323 g Cl2 × = 4.56 mol Cl2
1 mol Cl2
70.91 g Cl2
actual = 4.55 mol Cl2/mol P4
theoretical = 6.00 mol Cl2/mol P4
Chlorine gas is the limiting reagent.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 24 of 29
4-5 Other Practical Matters in
Reaction Stoichiometry
Theoretical yield is the expected yield from a reactant.
Actual yield is the amount of product actually produced.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 25 of 29
Theoretical, Actual and Percent Yield
When actual yield = % yield the reaction is said to be quantitative.
Side reactions reduce the percent yield.
By-products are formed by side reactions.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 26 of 29
Consecutive Reactions,
Simultaneous Reactions and
Overall Reactions
Multistep synthesis is often unavoidable.
Reactions carried out in sequence are called consecutive reactions.
When substances react independently and at the same time the reaction is a simultaneous reaction.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 27 of 29
Overall Reactions and Intermediates
The Overall Reaction is a chemical equation that expresses all the reactions occurring in a single overall equation.
An intermediate is a substance produced in one step and consumed in another during a multistep synthesis.
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 28 of 29
Focus on Industrial Chemistry
Prentice-Hall © 2002
General Chemistry: Chapter 4
Slide 29 of 29
Chapter 4 Questions
1, 6, 12, 25, 39, 45, 53, 65, 69, 75, 84, 94, 83, 112
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